2c^2=19c+33

Solution for 2c^2=19c+33 equation:

Simplifying
2c2 = 19c + 33

Reorder the terms:
2c2 = 33 + 19c

Solving
2c2 = 33 + 19c

Solving for variable 'c'.

Reorder the terms:
-33 + -19c + 2c2 = 33 + 19c + -33 + -19c

Reorder the terms:
-33 + -19c + 2c2 = 33 + -33 + 19c + -19c

Combine like terms: 33 + -33 = 0
-33 + -19c + 2c2 = 0 + 19c + -19c
-33 + -19c + 2c2 = 19c + -19c

Combine like terms: 19c + -19c = 0
-33 + -19c + 2c2 = 0

Factor a trinomial.
(-3 + -2c)(11 + -1c) = 0

Subproblem 1
Set the factor '(-3 + -2c)' equal to zero and attempt to solve:

Simplifying
-3 + -2c = 0

Solving
-3 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -2c = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -2c = 0 + 3
-2c = 0 + 3

Combine like terms: 0 + 3 = 3
-2c = 3

Divide each side by '-2'.
c = -1.5

Simplifying
c = -1.5
Subproblem 2
Set the factor '(11 + -1c)' equal to zero and attempt to solve:

Simplifying
11 + -1c = 0

Solving
11 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + -1c = 0 + -11

Combine like terms: 11 + -11 = 0
0 + -1c = 0 + -11
-1c = 0 + -11

Combine like terms: 0 + -11 = -11
-1c = -11

Divide each side by '-1'.
c = 11

Simplifying
c = 11
Solution
c = {-1.5, 11}